7^3x-1=(1/49)^1-x

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Solution for 7^3x-1=(1/49)^1-x equation: 



7^3x-1=(1/49)^1-x

We move all terms to the left:

7^3x-1-((1/49)^1-x)=0



Domain of the equation: 49)^1-x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

7^3x-((+1/49)^1-x)-1=0

We multiply all the terms by the denominator


7^3x*49)^1-x)-((-1*49)^1-x)+1=0

We add all the numbers together, and all the variables

7^3x*49)^1-x)-((-49)^1-x)+1=0

Wy multiply elements

343x^4-49)^1-x)+1=0

We do not support expression: x^4

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